School of Mathematics and Statistics
Junior
The University of Sydney
spcr

Quiz 11: One variable integration

Last unanswered question  Question  Next unanswered question
 

Question 1

 
 
Evaluate ∫ 1
   (6x2 - 4x+ 3) dx
 0  .
a) 4   b) -3
c) 3   d) 5

 

Not correct. Choice (a) is false.
Not correct. Choice (b) is false.
Your answer is correct.
∫
  1(6x2 - 4x+ 3) dx = [2x3 - 2x2 + 3x ]1 = 2- 2+ 3 = 3.
 0                                0
Not correct. Choice (d) is false.
 

Question 2

 
 
Evaluate ∫ π-
  2 (sinx + cosx ) dx
 0  .
a) 2   b) 0
c) π-
 2    d) -2

 

Your answer is correct.
∫ π
  2(sin x+ cosx) dx  =  [- cosx + sinx]π2
 0                                  0
                    =  - cos π-+ sin π-- (- cos 0+ sin0)
                            2      2
                    =  1+ 1 = 2.
Not correct. Choice (b) is false.
Not correct. Choice (c) is false.
Not correct. Choice (d) is false.
 

Question 3

 
 
Evaluate   π
∫ 4-
    sin 2x dx
 0  .
a) 1   b) 1
-
2
c)   1
- -
  2    d) -1

 

Not correct. Choice (a) is false.
Your answer is correct.
∫ π4             [        ]π4
   sin2x dx  =   - 1cos2x
 0                 2      0
             =  - 1cos π-+ 1 cos0
                  2   2   2
             =  1.
                2
Not correct. Choice (c) is false.
Not correct. Choice (d) is false.
 

Question 4

 
 
Evaluate ∫ √3         3
    x (1+ x2)2 dx
 0  .
a) 32
 5    b) 31
 5
c) 3
2    d) 9
2

 

Not correct. Choice (a) is false.
Your answer is correct.
  √-                             √-
∫  3 (     2) 32        [1     2 5] 3
 0  x 1 + x    dx  =    5(1+ x )2
                      1   5   1  0
                  =   - (4)2 - -
                      532   1  531
                  =   -- - - = --.
                       5   5   5
Not correct. Choice (c) is false.
Not correct. Choice (d) is false.
 

Question 5

 
 
Evaluate ∫ 2     3
   3x2ex dx
 0  .
a) e8 - 1    b) 8e8
c) - e8    d)    8
12e - 12

 

Your answer is correct.
∫ 2  2 x3     [ x3]2    8   0   8
 0 3x e  dx =  e  0 = e - e = e - 1.
Not correct. Choice (b) is false.
Not correct. Choice (c) is false.
Not correct. Choice (d) is false.
 

Question 6

 
 
Let A  be the area under the curve f(x) = 16 - x2 on the interval [0,4]. Dividing the interval into 4 subintervals and defining xi to be the midpoint of the ith interval (the area of the rectangle is thus f(xi) times the length of the interval), the best estimate for A is
a)    ∑4       2   1
A =   (16- xi)× 2
    i=1  , where      i--1
xi =  2
b)     ∑4
A =    (16- x2i)× 1
    i=1          2  , where xi = i-- 1
      2
c)     ∑4       2
A =    (16- xi)
    i=1  , where      2i--1
xi =   2
d)     ∑3
A =    (16- x2i)
    i=0  , where      2i- 1
xi = -----
       2

 

Not correct. Choice (a) is false.
Not correct. Choice (b) is false.
Your answer is correct.
The intervals are of length 1, and the area is calculated at 1
2, 3
2, 5
2 and 7
2.
Not correct. Choice (d) is false.
 

Question 7

 
 
Which of the following sums is the best estimate for A, the area under the curve f(x) = x3 + 2 on the interval [-1,2], divided into 6 subintervals and choosing xi as the right-endpoint of the ith interval ?
a)     6
A = ∑ (x3+ 2)
    i=0  i  , where xi = i--3
      2
b)     ∑6   3      1
A =    (xi + 2)× 2
    i=0  , where     2i - 1
xi =--2--
c)      6
A = ∑  (x3+ 2)
    i=1  i  , where xi = 2i--3
       2
d)     ∑6   3      1
A =    (xi + 2)× 2
    i=1  , where     i - 2
xi =--2-

 

Not correct. Choice (a) is false.
Not correct. Choice (b) is false.
Not correct. Choice (c) is false.
Your answer is correct.
The intervals are of length 1
2, and the area is calculated at -1
2, 0, 1
2, 1, 3
2, 2
 

Question 8

 
 
Find the indefinite integral ∫
   2t2(1+ t3)4 dt.
a) 1
-(1+ t3)5 + C
5    b) 2     3 5
5 (1 + t) + C
c) 2 t3(1+ t3)5 + C
3    d) -2     3 5
15 (1 + t) + C

 

Not correct. Choice (a) is false.
Not correct. Choice (b) is false.
Not correct. Choice (c) is false.
Your answer is correct.
Let u = 1 + t3, du = 3t2 dt  .
∫   2     34       2 ∫  4
   2t(1+ t )dt  =  3   u  du
                    2
                =  -- u5 + C
                   152
                =  -- (1 + t3)5 + C.
                   15
 

Question 9

 
 
Find the indefinite integral ∫
   sin3xcosx dx.
a) sin4x + C   b) 1
4 sin4x + C
c) 3sin2x + C   d)   1   4
- 4 sin x+ C

 

Not correct. Choice (a) is false.
Your answer is correct.
Let u = sinx, du = cosx dx.
∫                  ∫
  sin3 xcosx dx  =    u3 du

                =  1u4 + C
                   4
                =  1 sin4x + C.
                   4
Not correct. Choice (c) is false.
Not correct. Choice (d) is false.
 

Question 10

 
 
Find the indefinite integral
∫
  ---2t--e-t +-4---dt.
  (t2 + 4t+ e-t + 1)2
a) -------1------
t2 + 4t+ e-t + 1 + C    b) --------- 1-------+ C
3(t2 + 4t+ e-t + 1)3
c) -2------1-t--- + C
t + 4t+ e  + 1    d) ---------1--------+ C
3(t2 + 4t+ e-t + 1)3

 

Not correct. Choice (a) is false.
Not correct. Choice (b) is false.
Your answer is correct.
Let u = t2 + 4t+ e-t + 1  , du = (2t+ 4- e-t) dt.
∫          -t              ∫
   ---2t--e--+-4----dt =     -1 du
   (t2 + 4t+ e-t + 1)2        u2
                       =   - u-1 + C
                           ------- 1-----
                       =   t2 + 4t+ e-t + 1 + C.
Not correct. Choice (d) is false.