School of Mathematics and Statistics
Junior
The University of Sydney
spcr

Quiz 6: One variable optimisation

Last unanswered question  Question  Next unanswered question
 

Question 1

 
 
Find the relative growth rate of the function P (t) = 10e0.3t  .

 

Your answer is correct
The relative growth rate is   ′
P-(t)-
P (t)  .
Not correct. You may try again.
Remember that the relative growth rate is P-′(t)
 P(t)  .
 

Question 2

 
 
Let f(x) = x3 - 3x2 + 7  . Which of the following statements are correct?
a) The graph of y = f(x) has only one turning point, at x = 2.   b) The absolute maximum value of f(x) is 7.
c) The graph of y = f(x) has a local maximum at x = 0.   d) The graph of y = f(x) has a local minimum at x = 0.
e) The graph of y = f(x) has one point of inflexion.

 

There is at least one mistake.
For example, choice (a) should be false.
There is at least one mistake.
For example, choice (b) should be false.
There is a local maximum value of 7, but it is not the absolute maximum.
There is at least one mistake.
For example, choice (c) should be true.
There is at least one mistake.
For example, choice (d) should be false.
There is a local maximum at x = 0.
There is at least one mistake.
For example, choice (e) should be true.
Your answers are correct
  1. False.
  2. False. There is a local maximum value of 7, but it is not the absolute maximum.
  3. True.
  4. False. There is a local maximum at x = 0.
  5. True.
 

Question 3

 
 
Find the absolute maximum of the function          x+ 3
f(x) = x2 +-x-- 2  on the interval -2 x 1.
a) - 2-
  18    b) -10
c) -1   d) -5

 

Not correct. Choice (a) is false.
Not correct. Choice (b) is false.
Your answer is correct.
f′(x) = - (x-+-5)(x-+-1)
         (x + 2)(x - 1)
So the critical value of f on the given interval is at x = -1.
Now f(-1) = -1 and f(-2) = f(1) = -∞ so the absolute maximum of the function is -1.
Not correct. Choice (d) is false.
 

Question 4

 
 
Find the absolute minimum of the function       t2 + 2t
f(t) =---t--
        e  on the interval -2 t 2.
a)     √ -
2--2√--2
 e-  2    b) √ -
  2
c) 2 + 2√2
---√2--
  e    d) -√-
 2

 

Your answer is correct.
f′(x) = - 2--t2
          et
Critical points are at t = ±√ -
  2. There is a minimum at t = -√ -
  2.
              √-
f(- √2) = 2--2√-2-≈ - 3.41
           e- 2
f(2) = 1.08, f(-2) = 0
therefore the absolute minimum is     √ -
2--2√--2
 e- 2  at t = -√2-.
Not correct. Choice (b) is false.
This is a critical point.
Your answer is correct.
This is the absolute maximum.
Not correct. Choice (d) is false.
This is a critical point.
 

Question 5

 
 
Find the points of inflexion of the function f(x) = x4 - 12x3 + 6x - 9  on the interval -2 x 10.
a) x = 0, 6   b) x = 0, -6
c) x = ±√6-   d) x = ±√ --
  12

 

Your answer is correct.
 f(x) =   x4 - 12x3 + 6x - 9
f′(x) =   4x3 - 36x2 + 6
 ′′           2
f (x) =   12x - 72x
 ′′
f (x) = 0  when    2
12x - 72x = 0 ⇒ x(x - 6) = 0
So x = 0, x = 6.
Not correct. Choice (b) is false.
Not correct. Choice (c) is false.
Not correct. Choice (d) is false.
 

Question 6

 
 
Find the points of inflexion of the function               2
f(x) = sin2x + x  on the interval         π
0 ≤ x ≤ 2-  .
a) 0, π-
4    b) 0, π-
2
c) π-
 6  , 5π-
 6    d)  π
12  , 5π
12-

 

Not correct. Choice (a) is false.
Not correct. Choice (b) is false.
Not correct. Choice (c) is false.
Your answer is correct.
 f(x)  =  sin2x+ x2
 f′(x)  =  2 cos2x + 2x
 ′′
f (x)  =  - 4sin 2x+ 2
f′′(x) = 0  when   1
4(-- sin2x) = 0
  2  i.e when         1
sin2x = -
        2
i.e
       π  5π
2x  =  --,---
       6π 65π
 x  =  -- ,--.
       12  12
 

Question 7

 
 
The graph below is of the function y = f(x).
0.6 q4q9.eps
Which of the following statements gives reasonable values for x which satisfy the conditions.
a) f′(x) < 0  when -1 < x < 3
f′′(x) < 0  when x > 1
f′(x) > 0  and f′′(x) = 0  when x = 1.
  b) f′(x) < 0  when -1 < x < 3
f′′(x) < 0  when x > 1
f′(x) > 0  and f′′(x) = 0  for no value of x.
c) f′(x) < 0  when x < -1 and x > 3
f′′(x) > 0  when x < 1
f′(x) > 0  and f′′(x) = 0  when x = 1.
  d) f′(x) < 0  when x < -1 and x > 3
f′′(x) > 0  when x < 1
f′(x) > 0  and f′′(x) = 0  for no value of x.

 

Not correct. Choice (a) is false.
Not correct. Choice (b) is false.
Your answer is correct.
Not correct. Choice (d) is false.
 

Question 8

 
 
The graph below is of the function y = f(x).
0.6 q4q10.eps
Which of the following statements gives reasonable values for x which satisfy the conditions.
a) f′(x) < 0  when x < 1 and 5 < x < 7
f′′(x) > 0  when 3 < x < 6
f′(x) > 0  and f′′(x) = 0  when x = 6.
  b)  ′
f (x) < 0  when 1 < x < 5 and x > 7
 ′′
f (x) > 0  when 3 < x < 6
 ′
f (x) > 0  and  ′′
f (x) = 0  when x = 6.
c)  ′
f (x) < 0  when x < 1 and 5 < x < 7
 ′′
f (x) > 0  when x < 3 and x > 6
 ′
f (x) > 0  and  ′′
f (x) = 0  when x = 3.
  d)  ′
f (x) < 0  when 1 < x < 5 and 5 < x < 7
 ′′
f (x) > 0  when x < 3 and x > 6
 ′
f (x) > 0  and  ′′
f (x) = 0  when x = 3.

 

Not correct. Choice (a) is false.
Your answer is correct.
Not correct. Choice (c) is false.
Not correct. Choice (d) is false.
 

Question 9

 
 
How many turning points are there on a graph of y = ex +sinx + 2x  ?

 

Your answer is correct
dy-
dx > 0  for all x  , so there are no turning points.
Not correct. You may try again.
Note that dy-
dx > 0  for all x  .
 

Question 10

 
 
Find the value of P  at which the graph of       --2----
P(t) = 1+ e-t  has a point of inflexion.

 

Your answer is correct
P′′(t) = 0  when t = 0  .
Not correct. You may try again.
       2e-t(e- t - 1)
P′′(t) =--------t3--
         (1 + e )