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Differentiating the Exponential Function Quiz

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Web resources available

This quiz tests the work covered in Lecture 13 and corresponds to Section 3.2 of the textbook Calculus: Single and Multivariable (Hughes-Hallett, Gleason, McCallum et al.).
There are more web quizzes at Wiley, select Section 2.

Section 3.6 of The Mathematics Learning Centre’s booklet on differentiation Introduction to Differential Calculus covers differentiating the exponential function.

There are not very many sites that are useful for this topic but there is a useful graphic at http://www.ies.co.jp/math/java/calc/e˙diff/e˙diff.html.

Question 1

Which of the following is the derivative of $t g(t) = 5 ?$

a)	$′ t g (t) = (ln5)5.$	b)	$g′(t) = (lna)5t.$
c)	$g′(t) = (ln5)5x.$	d)	$1 t g′(t) = ln-55.$

Your answer is correct.

$-d(at) = (ln a)at. dt$

Not correct. Choice (b) is false.

Try again, $d-(at) = (lna)at dt$ and $a = 5.$

Not correct. Choice (c) is false.

Try again, we are differentiating with respect to $t$ , not $x$ .

Not correct. Choice (d) is false.

Try again, $d t t dt(a) = (lna)a .$

Question 2

Which of the following is the derivative of $y = 3x2 + 2ex?$

a)	$dy dx-= 3x2 + 2ex.$	b)	$dy- x dx = 5x +2e .$
c)	$dy-= 6x+ 2e. dx$	d)	$dy-= 6x+ 2ex. dx$

Not correct. Choice (a) is false.

Try again, you have not differentiated the first term.

Not correct. Choice (b) is false.

Try again, you have not differentiated the first term correctly.

Not correct. Choice (c) is false.

Try again, you have not differentiated the last term correctly.

Your answer is correct.

The derivative of $x2$ is $2x$ and the derivative of $x e$ is $x e$ so
$dy x x dx-= 3(2x)+ 2(e ) = 6x+ 2e .$

Question 3

Which of the following is the equation of tangent to $x y = 2 - 2e$ at $x = 1.$

a)	$y = - 2x.$	b)	$y = 8.732- 5.4336x.$
c)	$y = 2e- 2x.$	d)	$y = 2- (2e)x$

Not correct. Choice (a) is false.

Try again, this is equation of the tangent at $x = 0.$

Not correct. Choice (b) is false.

Try again, you have the correct gradient but the intercept is incorrect.

Not correct. Choice (c) is false.

Try again, you seem to have confused the gradient and the intercept.

Your answer is correct.

$dy ---= - 2ex dx$ so $dy|| --|| = - 2e. dx x=1$
The gradient of the tangent is therefore $- 2e$ and $y = (- 2e)x+ b.$
At $x = 1, y = 2- 2e$ and the tangent must pass through this point so we substitute these values into the equation of the line to find $b.$
$2 - 2e = - 2e(1)+ b ⇒ b = 2$ and $y = (- 2e)x+ 2 = 2- (2e)x.$

Question 4

We saw that if the population of a city increases at a rate which is proportional to the current population and was 2 million in 1980 and 2.5 million in 1990 then the formula for the population $t$ years after 1980 was given by $P (t) = 2e0.0223t.$ Which of the following correctly gives the population in the form $P(t) = P at, 0$ and the growth rate of $t$ years after 1980, to 4 decimal places?

a)	$P(t) = 2(1.0226)t, P′(t) = 2(1.0226)t$	b)	$P(t) = 2(1.0226)t, P′(t) = 0.0446(1.0226)t$
c)	$P (t) = (2.0452)t, P ′(t) = ln(2.0452)(2.0452)t$	d)	$P (t) = (2.0452)t, P ′(t) = 4.094(2.0452)t$