Consider a block on a plane inclined from the horizontal by the angle
.
The magnitude of the friction force F acting on the block is assumed to satisfy
| (1) |
where
is the coefficient of friction and N the force acting normal to the plane.
Determine the angle of critical equilibrium, that is, the maximal angle at which the
block will stay still.
For the block to stay still the total force must be zero:

Now choose a coordinate system such that the x-axis is parallel to the inclined plane and the y-axis is pointing upwards.
Writing R = Fxi, N = Nyj and G = Gxi + Gyj we get
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Using (1 ) we deduce that

Hence the block stands still if and only if
> tan
, so the critical angle is
= tan -1
.